std::future_status
Specifies state of a future as returned by wait_for and wait_until functions of std::future and std::shared_future. Constants
python
The issue here is that the future = m.make_future_dataframe method creates a dataset future where the only column is the ds date column. In order to predict using a model with regressors
Standard library header <future> (C++11)
future (const future &) = delete; ~future (); future & operator =(const future &) = delete; future & operator =(future &&) noexcept; shared_future <R> share () noexcept; // retrieving the value
std::future<T>::wait_until
wait_until waits for a result to become available. It blocks until specified timeout_time has been reached or the result becomes available, whichever comes first. The return value indicates why
std::promise
The promise is the "push" end of the promise-future communication channel: the operation that stores a value in the shared state synchronizes-with (as defined in std::memory_order)
python
However, this is many years in the future, giving affected decorators plenty of time to update their code. Make the future import a no-op in the future: Instead of eventually making from
std::future
The class template std::future provides a mechanism to access the result of asynchronous operations: An asynchronous operation (created via std::async, std::packaged_task,
std::future<T>::get
The get member function waits (by calling wait ()) until the shared state is ready, then retrieves the value stored in the shared state (if any). Right after calling this function, valid () is false.
How can one await a result of a boxed future?
impl<F> Future for Box<F> where F: Unpin + Future + ?Sized, Boxed futures only implement the Future trait when the future inside the Box implements Unpin. Since your function
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